Greatest Common Divisor

Problem #26

Tags: arithmetic modulo classical if-else c-0 popular-algorithm

Who solved this?

Also available in: Spanish Slovak Russian

It looks like none of beginner's courses on programming avoids practicing Euclid's algorithm for calculation of the greatest common divisor of two numbers.

Greatest Common Divisor or GCD of a and b is such an integer value c that both of a, b are divisible by it (e.g. leave no remainder) - and also c is the largest possible. For example gcd(20, 35) = 5 and gcd(13, 28) = 1. Euclid's algorithm is quite simple - we keep on subtracting smaller value (of a and b) from larger - and repeat this operation until values become equal - this last value will be gcd. For speeding up the process we can use modulo operation instead of subtraction.

For example:

20      35      - subtract first from second
20      15      - subtract second from first
5       15      - now subtract first from second twice
5       5       - and here is GCD

Least Common Multiple (or LCM) of a and b is such an integer d that it is divisible by both of them (and is the smallest of all possible). It can be found with the following rule:

lcm(a, b) = a * b / gcd(a, b)

By the way, if this task feels too easy, check the advanced LCM of a range version!

The task

Input data contain number of test-cases in the first line.
Then lines with test-cases follow, each containing two numbers - for A and B.
Answer should contain GCD and LCM for each pair, surrounded by brackets and separated by spaces, for example:

input data:
2
2 3
4 10

answer:
(1 6) (2 20)
You need to login to get test data and submit solution.